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5 July, 11:51

For whatvalue of a is 8x-8+3ax=5ax-2a an identity?

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  1. 5 July, 12:27
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    Identity means that equation is true no matter what.

    So we just need to rearrange equation.

    8x - 8 + 3ax = 5ax - 2a

    (8+3a) x - 8 = (5a) x - 2a

    Subtract both sides by 5ax

    (8+3a-5a) x - 8 = - 2a

    (8-2a) x - 8 = - 2a

    Now add both sides by 8

    (8-2a) x = 8-2a

    Notice that coefficient of x in left side is same as constant in right side.

    For equation to be true, no matter what value of x, 8-2a must be 0

    Set 8-2a equal to 0

    8-2a = 0

    8 = 2a

    a = 4

    Final answer: a = 4
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