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8 June, 03:51

A container has red blue and white marbles. Four times the number of white marbles exceeded 9 times the number of red marbles by 10. The ratio of blue marbles to red marbles was 3 to 1. There is a total of 65 marbles of all 3 colors. Form a system of equations with variables red marble: r, white marble: w, and blue marble: b. Solve the system of equations to find the number of white, red and blue marbles in the container.

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  1. 8 June, 06:48
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    First we need to get some expressions:

    "Four times the number of white marbles" = 4*w

    "9 times the number of red marbles" = 9*r

    " ... exceeded ... by 10": So 4*w is 10 more than 9*r or 4*w = 9*r + 10

    "ratio of blue marbles to red marbles is 3 to 1" : b/r = 3/1

    b=3*r

    "there is a total of 65 marbles": b+r+w=65

    So our system becomes

    b = 3*r

    65 = b+r+w

    4*w = 9*r+10

    The first equation allows us to substitute immediately into the second equation so

    65 = 4*r+w

    however, we can divide the third equation by 4 to get w:

    w = (9*r) / 4+10/4

    This can then be plugged into the second to get:

    65 = 4*r + (9*r) / 4+10/4 = (16*r) / 4 + (9*r) / 4+10/4 = (25*r+10) / 4

    260 = 25*r+10

    250 = 25*r

    r=10

    Now we simply plug this result into the substitutions to get w and b:

    w = 90/4+10/4 = 100/4 = 25

    b=30

    So there are 10 red marbles, 25 white marbles, and 30 blue marbles

    Now it sounds like we should be picking some out at random; )
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