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20 July, 19:53

What are the solutions to 2x^2+7x=4?

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  1. 20 July, 20:24
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    2x^2+7x-4=0

    2x^2+8x-x-4=0

    2x (x+4) - 1 (x+4) = 0

    (2x-1) (x+4) = 0

    So the zeros or solutions occur when x=-4 and 1/2
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