Find the area and perimeter of a triangle whose angles are all 60 degrees and base is 8m

If the angles are all 60 degress, then the triangle must be an equilateral triangle which hse all 3 sides equal so if 1 sides is 8 in length then the other sides must be 8 in legnth also

permimiter=3 times 8=24m

area=1/2 times base times height

base=8

height=use pythagorean theorem

a^2+b^2=c^2

a=4

c=8

solve for b

4^2+b^2=8^2

16+b^2=64

subtract 16 from both sdies

b^2=48

squar root both sdies

b=4 times squareroot3=height

so 1/2 times base times height

1/2 times 8 times 4 times squareroot 3

16 times square root 3

area=4√3 meters

The perimeter is 24m and the area is 64m