Dana wants to make two types of dog treats. She has 10 cups of peanut butter and 12 cups of flour. Her dog bone treat recipe uses 3 cups of peanut butter and 2 cups of flour to make one tray. A tray of her oatmeal dog treat recipe uses 1 cup of peanut butter and 4 cups of flour. She plans to sell trays of dog treats at the town festival and charge $6 for a tray of dog bone treats and $7 for a tray of oatmeal treats. Dana wants to maximize her income from selling the dog treats.

When writing constraints for the problem, what is the most reasonable definition for the variables x and y?

Question

Mathematics

August Herrera

4 October, 02:56

Dana wants to make two types of dog treats. She has 10 cups of peanut butter and 12 cups of flour. Her dog bone treat recipe uses 3 cups of peanut butter and 2 cups of flour to make one tray. A tray of her oatmeal dog treat recipe uses 1 cup of peanut butter and 4 cups of flour. She plans to sell trays of dog treats at the town festival and charge $6 for a tray of dog bone treats and $7 for a tray of oatmeal treats. Dana wants to maximize her income from selling the dog treats.

When writing constraints for the problem, what is the most reasonable definition for the variables x and y?

+4

Answers (2)

Know the Answer?

Felix Macdonald · Answer 1

The variable x and y will stand for the peanut butter and flour.

x can be the peanut butter while y can be the flour. The constraints are:

x = 10 cups

y = 12 cups

dogbone treat: 3x + 2y

oatmeal dog treat: x + 4y

Johanna Reid · Answer 2

The most reasonable definitions for the variables x and y when writing constraints for the problem are as follows:

Let x = number of trays of the treats (whether oatmeal or peanut better)

Let y = maximum income from selling the dog treats

Furthermore, it can be expressed through the equation:

y = 6x + 7x