Suppose you got 8 mangoes and 3 apples for $18 and 3 mangoes and 5 apples for $14.50. how mush does each mango and each apple cost.

Let m = cost of mangoes

a = cost of apples

8m+3a=18 total (first equation)

3m+5a=14.50 (Second Equation)

Solve using system of equations

8m+3a=18.00

3m+5a=14.50

Multiply 1st equation by 5 and second equation by - 3:

5 (8m+3a) = 5 (18.00)

-3 (3m+5a) = - 3 (14.50)

Your problem should look like:

40m+15a=90

-9m+-15a=-43.5

Then you cancel out the 15a and (-15a). So when you combine like terms you get: 31m=46.5

Divide each side by 31.

31m/31=46.5/31

m = 1.5

Then you plug in 1.5 into any of the original equation to find the cost of your apples.

3 (1.5) + 5a=14.5

4.5 + 5a = 14.5

5a=14.5-4.5

5a=10

a=2

Each Mango cost $1.50 and each apple costs $2.00

Suppose a mango cost x dollar and a apple cost y dollar

there will be an binary system of equation

8*x+3*y=18

3*x+5*y=14.5

so soultions have to x=48/31 y=16/31