Ask Question
15 April, 03:38

What is the complete factorization of the polynomial below

x^3-4x^2+x-4?

A. (x-4) (x+i) (x-1)

B. (x+4) (x+i) (x-i)

C. (x+4) (x-i) (x-i)

D. (x-4) (x-i) (x-i)

+4
Answers (1)
  1. 15 April, 06:10
    0
    The answer to this question is D. (x-4) (x-i) (x-i).

    x^3-4x^2+x-4 is divisible by (x-4) using Remainder theorem. Division leaves us with a quotient of x^2 + 1, which factors into (x-i) (x-i). Therefore all of the factors of (x-4) (x-i) (x-i).
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the complete factorization of the polynomial below x^3-4x^2+x-4? A. (x-4) (x+i) (x-1) B. (x+4) (x+i) (x-i) C. (x+4) (x-i) (x-i) D. ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers