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13 June, 14:41

How do you solve x^2+4x-5=0

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Answers (2)
  1. 13 June, 18:09
    0
    Try this option:

    1. root1*root2=-5; root1+root2=-4.

    2. root1=-5; root2=1.

    answer:1; -5.
  2. 13 June, 18:36
    0
    Actually the answer is (-1,5)

    x^2 - 4x - 5 = 0

    x^2 - 4x = 5

    x^2 - 4x + 4 = 5 + 4

    (x - 2) ^2 = 9

    x - 2 = ± 3

    x = 2 + 3 and x = 2 - 3

    x = 5 and x = - 1

    {-1, 5}
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