Brian has a bag that contains 14 red marbles and 12 yellow marbles. He selects a marble at random, and then, without replacing the first one, selects another marble at random. What is the probability that Brian selects a red marble and then a yellow marble? Round your answer to the nearest percent.

Question

Mathematics

Guest

18 August, 02:11

Brian has a bag that contains 14 red marbles and 12 yellow marbles. He selects a marble at random, and then, without replacing the first one, selects another marble at random. What is the probability that Brian selects a red marble and then a yellow marble? Round your answer to the nearest percent.

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Answers (1)

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Max Lara · Answer 1

Answer=25%

14 red marbles

12 yellow marbles

26 total marbles

To solve this, we need to first find out the probability of the individual events ...

The odds of selecting a red marble is 14 out of 26 total marbles: 14/26

The odds of selecting a yellow marble after the first marble was NOT replaced is 12 out of 25. (25 since the first marble wasn't replaced: 26-1=25) 12/25

Now lets multiple both probabilities together to solve for the chance of both happening consecutively ...

14/26*12/25 = 168/650=84/325

84/325 = 0.25846153846 = 25%