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28 July, 17:57

Find the number of real number solutions for the equation.

x^2-4x+4=0

A-1

B-0

C-cannot be determined

D-2

+4
Answers (1)
  1. 28 July, 21:44
    0
    X² - 4x + 4 = 0

    (x-2) (x-2) = 0

    the equation has one root mainly 2 with multiplicity 2

    the answer is a
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