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17 July, 15:31

Evaluate the integral: ∫dx / (sqrt ((x^2) + 16))

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  1. 17 July, 16:08
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    Let x=4tanβ, then dx = 4sec²βdβ. Now

    ∫ (4sec²β) / (4secβ) dβ

    = ∫secβdβ

    = ln |tanβ - secβ| + c

    = ln | (x/4) - (√ (x²+16) / 4| + C

    = ln |x/√ (x²+16)
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