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28 March, 12:46

Given that n=a3b4c5 where a, b and c are distinct prime numbers, what is the smallest number with which n should be multiplied such that it becomes a perfect square, a perfect cube as well as a perfect fifth power?

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  1. 28 March, 13:27
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    A^27b^26c^25 would be the smallest number.

    This yields a^30b^30c^30.
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