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Mathematics
Keith Livingston
24 June, 15:09
9x^2-12x+4=4 how to sove by square root property
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Jarrett Flowers
24 June, 18:20
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Solve for x over the real numbers using the quadratic formula.
9 x^2 - 12 x + 4 = 4
Subtract 4 from both sides:
9 x^2 - 12 x = 0
9 x^2 - 12 x = 3 (3 x^2 - 4 x):
3 (3 x^2 - 4 x) = 0
Divide both sides by 3:
3 x^2 - 4 x = 0
x = (4 ± sqrt ((-4) ^2 - 4*3*0)) / (2*3) = (4 ± sqrt (16 + 0)) / 6 = (4 ± sqrt (16)) / 6 = (4 ± 4) / 6:
x = (4 + 4) / 6 or x = (4 - 4) / 6
(4 + 4) / 6 = 8/6 = 4/3:
x = 4/3 or x = (4 - 4) / 6
(4 - 4) / 6 = 0/6 = 0:
Answer: x = 4/3 or x = 0
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