Ask Question
26 February, 11:20

What average force is needed to accelerate a 9.20-gram pellet from rest to 125 m/s over a distance of 0.800 m along the barrel of a rifle?

+1
Answers (1)
  1. 26 February, 14:22
    0
    Given:

    u = 0, initial velocity

    v = 125 m/s, final velocity

    s = 0.0800 m, distance traveled

    9.20 g, the mass of the pellet

    If the acceleration is a, then

    0² + 2 * (a m/s²) * (0.800 m) = (125 m/s) ²

    1.6a = 15625

    a = 9765.625 m/s²

    Calculate the force.

    F = (9.20 x 10⁻³ kg) * (9765.625 m/s²) = 98.84 N

    Answer: 98.8 N (nearest tenth)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What average force is needed to accelerate a 9.20-gram pellet from rest to 125 m/s over a distance of 0.800 m along the barrel of a rifle? ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers