2) A velocity vector has components 36 m/s westward and 22 m/s northward. What are the magnitude and direction of this vector?

The magnitude:

→

| a | = √ (22² + 36²) = √ (484 + 1296) = √ 1780 = 42.19 m/s

The direction:

tan α = 22/36 = 0.61111

α = tan^ (-1) 0.61111 = 31.43 ° = 31° 26'

Answer:

The magnitude is 42.19 m/s and the direction is 31° 26'north from west.