A box of mass 3.0 kg is accelerated from rest across a floor at a rate of 3.0 m/s2 for 4.0 s. what is the net work

Work done is given by multiplying force and distance.

Therefore; W = Force * distance

but from the second newton's law of motion F=ma

Therefore; W = (ma) * d

Using; V = U + at

V = 0 + (3*4)

V = 12 m/s

But d = (V+U) / 2 (t)

d = 12/2 (4)

= 24 M

Hence; W = (3 * 3) * 24

= 216 J