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25 January, 00:21

A circular swimming pool has a diameter of 24 ft, the sides are 5 ft high, and the depth of the water is 4 ft. how much work is required to pump all of the water out over the side? (use the fact that water weighs.) 62.5 lb

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  1. 25 January, 00:47
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    The pumping work has the equation written below:

    W = mΔh,

    where m is the mass

    Δh is the difference in height

    We determine the mass from the density of water which is 62.5 lb/ft³.

    Density = Mass/Volume

    Mass = m = Density*Volume

    m = (62.5 lb/ft³) (π/4) (24 ft) ² = 9,000π

    The lb is in lbm or pound-mass. To convert it to pound-force, lbf, we use the g/gc conversion factor which is equal to 1 lbf/lbm. Thus,

    W = (9,000π lbm) (5 ft - 4 ft) (1 lbf/lbm) = 28,274 lbf·ft
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