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10 July, 13:29

A 60 W lightbulb is on for 24 hours. A stereo with a power of 150 W is on for 2 hours. Which statement correctly compares the energy used by these devices?

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  1. 10 July, 14:43
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    P=∆E/∆t. ∆E=P*∆t

    Lightbulb: ∆E=60 * (24*3600) the unit of the time has to be seconds

    Stereo: ∆E = 50 * (2*3600)
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