Two rockets having the same acceleration start from rest, but the first rocket travels for twice as much time as the second one. If rocket A goes for 310 km, how far will B go? If rocket A reaches a speed of 320, what speed will rocket B reach?

Let ta be the time the first rocket travels and tb be the time the second rocket travels. ta = 2tb

We apply:

sa = ut + 1/2 at², with u = 0 since they start from rest.

310000 = 1/2a (ta) ²

a = 620000 / 4 (tb) ²

sb = 1/2 a (tb) ²

sb = 1/2 x 620000 / 4 (tb) ² x (tb) ²

sb = 77.5 Km

We apply v = u + at, with u = 0

va = a (ta)

a = 320/2 (tb)

vb = a (tb)

vb = (320/2tb) (tb)

vb = 160