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11 February, 15:55

If an astronaut can throw a certain wrench 10.0 m vertically upward on earth, how high could he throw it on our moon if he gives it the same starting speed in both places?

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  1. 11 February, 17:19
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    I think you forgot to include the acceleration due to gravity of astronauts. I assume that it is = 0.170 g. To get the answer we have to use the formula s = v0t - (1/2) At². Where s is the altitude, A is the acceleration of gravity, t is the time after throwing.

    v = v0 - At

    v = 0 at max altitude so v0 - At = 0

    t = v0/A at max altitude

    Using the formula above for the altitude:

    s = v0t - (1/2) At²

    s = v0 (v0/A) - (1/2) A (v0/A) ²

    s = v0²/A - (1/2) v0²/A

    s = (1/2) v0²/A

    The earth: E = (1/2) v0²/g

    The moon: M = (1/2) v0² (0.17g)

    So, take the ratio of M/E = g/0.17g = 1/0.17 = 588

    M = 5.88 E

    He can throw the wrench 5.88 times higher on the moon

    M = 5.88 (10 m) = 58.8 meters that the can throw the wrench a little over on the moon.
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