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3 May, 17:04

A parallel circuit has two 8.0-ohm resistors and a power source of 9.0 volts. If a 12.5-ohm resistor is added to the circuit in parallel, how will the current be affected and what value will it have?

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  1. 3 May, 18:54
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    - - The two 8-ohm resistors in parallel are equivalent to

    a single 4-ohm resistor.

    - - The current in the circuit is

    (voltage) / (resistance) = (9v) / (4ohms) = 2.25 Amperes

    - - If another resistor is added in parallel, then no matter how large

    or small it is, the current in the circuit increases.

    (When another lane is added to a road, the traffic capacity of the

    road increases.)

    The circuit is now equivalent to a 12.5-ohm resistor in parallel

    with 4-ohms. That's ...

    (12.5 x 4) / (12.5 + 4) = 50/16.5 = 3.03 ohms.

    - - The new current is (9v) / (3.03 ohms) = 2.97 Amperes
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