Ask Question
4 September, 02:18

If you wished to warm 100 kg of water by 15 degrees celsius for your bath, how much heat would be required? (give your answer in calories and joules)

+1
Answers (1)
  1. 4 September, 05:31
    0
    For the answer to the question above,

    Q = amount of heat (kJ)

    cp = specific heat capacity (kJ/kg. K) = 4.187 kJ/kgK

    m = mass (kg)

    dT = temperature difference between hot and cold side (K). Note: dt in °C = dt in Kelvin

    Q = 100kg * (4.187 kJ/kgK) * 15 K

    Q = 6,280.5 KJ = 6,280,500 J = 1,501,075.5 cal
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If you wished to warm 100 kg of water by 15 degrees celsius for your bath, how much heat would be required? (give your answer in calories ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers