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20 March, 00:41

A 300 kg dragster accelerates from the rest to the final speed of 120 m/s in 400 m (about a quarter of a mile) and encounters an average frictional force of 1200 N. What is the average output in watts AND horsepower if this takes 7.30 seconds?

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  1. 20 March, 04:03
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    This problem involves Work and Power

    Given: Mass m = 300 Kg; Initial Velocity Vi = 0; Final Velocity Vf = 120 m/s

    Distance d = 400 m; Frictional force Ff = 1200 N; Time t = 7.30 s

    Frictional Force Ff = 1200 N acting opposite of the Force

    Required: Power = ? in unit of watts and Horsepower

    Formula: P = W/t F = ma Work = Force x distance or W = fd; a = Vf - Vi/t

    F = ma F = m (Vf - Vi) / t F = (300 Kg) (120 m/s - 0 m/s) / 7.30 s

    F = 4, 931.16 N

    Force total = Force - Frictional force or Ft = F - Ff

    Ft = 4, 931.16 N - 1200 N = 3,731.16 N

    P = W/t = P = F. d/t P = (3, 731.16 N) (400 m) / 7.3 s P = 204, 447.12 N m/s or in unit of watts / convert / or multiply this number to 0.00134102 Hp

    Convert to Horsepower Hp = 278
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