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7 October, 16:54

If you wish to warm 100 kg of water by 20°C for your bath, how much heat is required? (Give your answer in calories and joules.)

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  1. 7 October, 19:24
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    Q = mcθ

    Where m = mass of water in kg.

    c = specific heat capacity in kJ/kg⁰C, c for water = 4200 kJ/kg⁰C

    θ = temperature rise in ⁰C

    Q = 100*4200 * 20 Note here the temperature rise is 20 ⁰C

    Q = 8 400 000 J

    In calories, 4.2 J = 1 Calorie

    = 8 400 000 / 4.2 = 200 000

    Q = 200 000 Calories
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