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7 July, 06:20

What current would it need to carry in order to experience a very modest 1.0*10-3n⋅m torque?

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  1. 7 July, 08:53
    0
    By using the formula:

    Tau = (I) (A) (B) Sinθ

    Get the area first of the circle:

    A = πr^2

    A = π (0.08m) ^2

    A = 0.02011 m^2

    Then solve,

    B (earth) = 5x10^-5 T

    θ = 0, since the angle of the wire is oriented for maximum torque in the earth's field. Which means the angle is 0.

    Reorder the formula to solve for the charge (I):

    I = (tau) / (A) (B) Sinθ

    I = (tau) / (A) (B)

    I = (1.0x10^-3) / (0.02011) (5x10^-5)

    I = 994 A
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