A tennis ball is thrown straight up with an initial speed of 22.5 m/s. It is caught at the maximum height of its arc.

a. How high does the ball rise? 25.83 m

b. How long does the ball remain in the air?

To calculate the maximum height, we can use:

2as = v² - u²; where v is 0 at the maximum height, a is - 9.81 m/s² and u is 22.5 m/s

2 x - 9.81s = - (22.5) ²

s = 25.8 m, your answer is correct.

The time of flight of the ball can be given by:

v = u + at; v = 0 at max height

0 = 22.5 - 9.8t

t = 2.30 seconds

It is caught at its maximum height so its time in the air is 2.30 seconds.