Ask Question
14 November, 00:57

If atmospheric pressure suddenly changes from 1.00 atm to 0.896 atm at 298 k, how much oxygen will be released from 3.30 l of water in an unsealed container?

+5
Answers (1)
  1. 14 November, 02:07
    0
    At a temperature of 298 K, the Henry's law constant is 0.00130 M/atm for oxygen. The solubility of oxygen in water 1.00 atm would be calculated as follows:

    S = (H) (Pgas) = 0.00130 M / atm x 0.21 atm = 0.000273 M

    At 0.890 atm,

    S = (H) (Pgas) = 0.00130 M / atm x 0.1869 atm = 0.00024297 M

    If atmospheric pressure would suddenly change from 1.00 atm to 0.890 atm at the same temperature, the amount of oxygen that will be released from 3.30 L of water in an unsealed container would be as follows

    3.30 L x (0.000273 mol / L) = 0.0012012 mol

    3.30 L x (0.00024297 mol / L) = 0.001069068 mol

    0.0012012 mol - 0.001069068 mol = 0.000132 mol
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If atmospheric pressure suddenly changes from 1.00 atm to 0.896 atm at 298 k, how much oxygen will be released from 3.30 l of water in an ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers