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10 February, 22:13

A small puck with a mass of 0.10 kilograms is sliding in the + x-direction on an air table with an initial speed of 8.0 meters/second. The puck collides with a larger puck that is initially at rest. The larger puck has a mass of 0.40 kilograms. After the collision, the smaller puck has a speed of 3.4 meters/second at an angle of + 60° from its original path. The angle made by the larger puck is - 35°. What is the x-momentum after the collision if the velocity of the larger puck after the collision is 1.5 meters/second?

0.8 kilogram meters/second

1.5 kilogram meters/second

2.1 kilogram meters/second

3.6 kilogram meters/second

4.8 kilogram meters/second

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Answers (1)
  1. 10 February, 23:55
    0
    By definition we have the momentum is:

    p = m * v

    Where

    p: linear momentum

    m: mass

    v: speed.

    For this case, momentum is conserved!

    initial x momentum = 0.1kg * 8m / s = 0.8kg · m / s = final x-momentum

    All the rest is clutter.

    the answer is

    0.8 kilogram meters/second
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