A box rests on top of a flat bed truck. the box has a mass of m = 18 kg. the coefficient of static friction between the box and truck is Î¼s = 0.86 and the coefficient of kinetic friction between the box and truck is Î¼k = 0.69. 1) the truck accelerates from rest to vf = 16 m/s in t = 16 s (which is slow enough that the box will not slide). what is the acceleration of the box?

Question

Physics

Mario Henry

8 May, 16:01

A box rests on top of a flat bed truck. the box has a mass of m = 18 kg. the coefficient of static friction between the box and truck is Î¼s = 0.86 and the coefficient of kinetic friction between the box and truck is Î¼k = 0.69. 1) the truck accelerates from rest to vf = 16 m/s in t = 16 s (which is slow enough that the box will not slide). what is the acceleration of the box?

+2

Answers (1)

Know the Answer?

Danielle Cross · Answer 1

For this case, the first thing you should do is write the kinematic motion equation of the block.

We have then:

vf = vo + a * t

Where,

vf: Final speed.

vo: Initial speed.

a: acceleration.

t: time.

Substituting the values:

(16) = (0) + a * (16)

Clearing the acceleration:

a = 16/16 = 1m / s ^ 2

Note: the other data for this case are not used in this problem.

answer:

The acceleration of the box is 1m / s ^ 2