Assume patmos=1.00atm. what is the gas pressure pgas? express your answer in pascals to three significant figures.

Answer: Well, let's start by finding the pressure due to the "extra" height of the mercury. p = 1.36e4 kg/m³ · (0.105m - 0.05m) · 9.8m/s² = 7330 N/m² = 7330 Pa The pressure at B is clearly p_b = p_atmos = p_gas + 7330 Pa The pressure at A is p_a = p_gas = p_atmos - 7330 Pa c) 1 atm = 101 325 Pa Then p_gas = 101325 Pa - 7330 Pa = 93 995 Pa