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26 May, 03:24

A circuit node has current ia entering and currents ib and ic exiting, where it is known that ia=5 ma and ib=9 ma. what is current ic?

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  1. 26 May, 05:31
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    The current is the flow of electrons. It is expressed as Coulombs per second, or Amperes. Since it is a flow, all that comes in must go out. The basis here is the node. Since ia is the full flow, it must be greater than ib or ic. So, I think the given information is wrong. It should be ia = 9 mA and ib=5 mA.

    Current entering = Current leaving

    ia = ib + ic

    9 mA = 5 mA + ic

    ic = 9 mA - 5 mA = 4 mA
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