5. The moon's gravity is one-sixth that of the earth. What is the period of a 0.50 m long pendulum on the moon?

First, we are given that the gravity of moon is 1/6 the gravity of earth.

Knowing that the gravity of earth is 9.8, we can calculate the gravity of moon as follows:

gravity of moon = (1/6) * (9.8) = 1.63334 meter/sec^2

Now, the formula used to calculate the period is as follows:

T = 2*pi * sqrt (L/g)

where

T is the period we need to calculate

L is the length of pendulum = 0.5 m

g is the gravity = 1.63334 m/sec^2

Substitute with the givens in the equation to get the period as follows:

T = 2*3.14 * sqrt (0.5/1.63334)

T = 3.4746 seconds