A proton moving with a velocity of 4.0 * 104 m/s enters a magnetic field of 0.20 t. if the angle between the velocity of the proton and the direction of the magnetic field is 60°, what is the magnitude of the magnetic force on the proton? (e = 1.60 * 10-19

c.

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Joshua

30 December, 21:19

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Devan Hurley · Answer 1

F=qVBsin (60) = (1.60e-19) (4.0e4) (0.20) (0.866) = 1.1085 N

A proton moving with a velocity of 4.0 * 104 m/s enters a magnetic field of 0.20 t. if the angle between the velocity of the proton and the direction of the magnetic field is 60°, what is the magnitude of the magnetic force on the proton? (e = 1.60 * 10-19c.