Accomplished silver workers in india can pound silver into incredibly thin sheets, as thin as 3.00 10-7 m (about one-hundredth of the thickness of a sheet of paper). find the area of such a sheet that can be formed from 1.70 kg of silver.

The density of silver is ρ = 10500 kg/m³ approximately.

Given:

m = 1.70 kg, the mass of silver

t = 3.0 x 10⁻⁷ m, the thickness of the sheet

Let A be the area.

Then, by definition,

m = (t*A) * ρ

Therefore

A = m / (t*ρ)

= (1.7 kg) / [ (3.0 x 10⁻⁷ m) * (10500 kg/m³) ]

= 539.7 m²

Answer: 539.7 m²