A crate slides down a ramp that makes a 20∘ angle with the ground. to keep the crate from sliding too fast, paige pushes back on it with a 64 n horizontal force. part a how much work does paige do on the crate as it slides 3.6 m down the ramp?

The solution is:

Paige's force is (somewhat) against the direction of motion: Work = F * d Where F is the force; andd is the distance

Our f is 64 N and our distance is 20 and - 3.6Plugging that in our equation will give us:

= 64N * cos20º * - 3.6m = - 217 J