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28 November, 20:31

If? h°rxn and? s°rxn are both negative values, what drives the spontaneous reaction and in what direction at standard conditions?

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  1. 28 November, 21:42
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    The release of free energy drives the spontaneous reaction.

    Spontaneity can be determined using the change in Gibbs free energy (the thermodynamic potencial):

    delta G=delta H - T*delta S

    where delta H is the enthalpy and delta S is the entropy.

    The direction (the sign) of delta G depends of the changes of enthalpy and entropy. If delta G is negative then the process is spontaneous.

    In our case, both delta H and delta S are negative values, the process as said is spontaneous which means that it may proceed in the forward direction.
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