Meteorite On October 9, 1992, a 27-pound meteorite struck a car in Peekskill, NY, creating a dent about 22 cm deep.

If the initial speed of the meteorite was 480m/s, what was the average force exerted on the meteorite by the car?

Express your answer using two significant figures.

Question

Physics

Brody

25 September, 17:14

Meteorite On October 9, 1992, a 27-pound meteorite struck a car in Peekskill, NY, creating a dent about 22 cm deep.

If the initial speed of the meteorite was 480m/s, what was the average force exerted on the meteorite by the car?

Express your answer using two significant figures.

+5

Answers (1)

Know the Answer?

Camden Boyd · Answer 1

We can use:

2as = v² - u²

to find the deceleration of the meteorite:

a = - u²/2s

a = - (480²) / 2 x 0.22

= - 5.2 x 10⁵ m/s₂

Force = mass x acceleration

Mass in kg = 27/2.2

Force = 27/2.2 x 5.2 x 10⁵

= 6.4 x 10⁶ Newtons

Meteorite On October 9, 1992, a 27-pound meteorite struck a car in Peekskill, NY, creating a dent about 22 cm deep.If the initial speed of the meteorite was 480m/s, what was the average force exerted on the meteorite by the car?Express your answer using two significant figures.

Meteorite On October 9, 1992, a 27-pound meteorite struck a car in Peekskill, NY, creating a dent about 22 cm deep.

If the initial speed of the meteorite was 480m/s, what was the average force exerted on the meteorite by the car?

Express your answer using two significant figures.