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6 July, 17:48

When a quantity of monatomic ideal gas expands at a constant pressure of 4.00*104pa, the volume of the gas increases from 2.00*10-3m3 to 8.00*10-3m3?

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  1. 6 July, 19:36
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    Yes that is correct. We know this because 4.00 x 10 4 Pa is constant. If you have 2.00*10-3m3 then you do the following: (2.00*10^-3) (4.00*10^ 4) = 8.00*10^-3. That is how you get your answer
  2. 6 July, 21:18
    0
    This can be verified if we know the values of the initial (T1) and final (T2) temperatures. We use the ideal gas equation for this: PV=RT.

    P1V1=RT1

    (40000 Pa) * (0.002 m^3) = (8.314 m3Pa/molK) (T1)

    T1 = 9.62 K

    P2V2=RT2

    (40000 Pa) * (0.008 m^3) = (8.314 m3Pa/molK) (T2)

    T2 = 33.5 K

    Thus, this is true if the monoatomic ideal gas is heated from 9.62 K to 33.5 K at constant pressure.
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