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4 April, 05:20

A spaceship moving with an initial velocity of 58.0 meters/second experiences a uniform acceleration and attains a final velocity of 153 meters/second. What distance has the spaceship covered after 12.0 seconds? 6.96 * 102 meters 1.27 * 103 meters 5.70 * 102 meters 1.26 * 102 meters 6.28 * 102 meters

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  1. 4 April, 06:51
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    Given

    u→Initial velocity of the spaceship=58 ms

    v→after t = 12s, Final velocity of the spaceship = 153 ms

    The spaceship moving with uniform acceleration

    s→The distance covered in t s = 12 (u+v) * t = 12 (58+153) * 12 = 1266 m
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