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15 June, 02:13

A train with a constant velocity of + 28.6 m/s approaches a small town. the operator applies the brake, reducing the train's velocity to + 11.4 m/s. if the average acceleration of the train during braking is 1.35 m/s2, for what elapsed time does the operator apply the brake?

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  1. 15 June, 04:35
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    We shall use the formula

    v = u + at

    where

    v = final velocity

    u = intal velocity

    t = time

    a = acceleration

    For the given problem,

    v = 11.4 m/s (final elocity)

    u = 28.6 m/s (initial velocity)

    a = - 1.35 m/s^2 (negative acceleration for braking)

    Therefore

    11.4 = 28.6 - 1.35t

    1.35t = 28.6 - 11.4 = 17.2

    t = 17.2/1.35 = 12.7407 s

    Answer: 12.74 s
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