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20 October, 22:50

The concentration of ozone in los angeles is 0.67 ppm on a summer day. what is the partial pressure of o3 if the total pressure is 735 torr?

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  1. 21 October, 01:17
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    We use the Raoult's Law to answer this question.

    Partial Pressure = Mole Fraction*Total Pressure

    When concentration is expressed in ppm, it means 'parts per million'. So, there can be 0.67 mol of ozone per 10⁶ mol of mixture.

    Mole fraction = 0.67/10⁶ = 0.67*10⁻⁶

    Partial pressure = 0.67*10⁻⁶ (735 torr) = 4.92*10⁻⁴ torr
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