Ask Question
9 January, 10:42

Derive a relation between Universal Gravitational Constant (G) and Acceleration due to gravity (g) ?

+5
Answers (2)
  1. 9 January, 11:04
    0
    suppose earth is a soid sphere which will attract the body towards its centre. So, acc. to law of gravitation force on the body will be,

    F=G*m1m2/R^2

    but we now that F=ma

    and here accleration (a) = accleration due to gravity (g), so

    force applied by earth on will also be mg

    replace above F in formula by mg and solve,

    F=G*mE*m/R^2 (here mE is mass of earth and m is mass of body)

    mg=G*mEm/R^2

    so,

    g = G*mE/R^2
  2. 9 January, 14:25
    0
    Suppose earth is a soid sphere which will attract the body towards its centre. So, acc. to law of gravitation force on the body will be,

    F=G*m1m2/R^2

    but we now that F=ma

    and here accleration (a) = accleration due to gravity (g), so

    force applied by earth on will also be mg

    replace above F in formula by mg and solve,

    F=G*mE*m/R^2 (here mE is mass of earth and m is mass of body)

    mg=G*mEm/R^2

    so,

    g = G*mE/R^2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Derive a relation between Universal Gravitational Constant (G) and Acceleration due to gravity (g) ? ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers