Ask Question
22 June, 04:38

Consider a steel guitar string of initial length l=1.00m and cross-sectional area a=0.500mm2. the young's modulus of the steel is y=2.0*1011n/m2. how far (δl) would such a string stretch under a tension of 1500 n? express your answer in millimeters using two significant figures.

+5
Answers (1)
  1. 22 June, 07:35
    0
    L = 1.00 m, the original length

    A = 0.5 mm² = 0.5 x 10⁻⁶ m², the cross sectional area

    E = 2.0 x 10¹¹ n/m², Young's modulus

    P = 1500 N, the applied tension

    Calculate the stress.

    σ = P/A = (1500 N) / (0.5 x 10⁻⁶ m²) = 3 x 10⁹ N/m²

    Let δ = the stretch of the string.

    Then the strain is

    ε = δ/L

    By definition, the strain is

    ε = σ/E = (3 x 10⁹ N/m²) / (2 x 10¹¹ N/m²) = 0.015

    Therefore

    δ / (1 m) = 0.015

    δ = 0.015 m = 15 mm

    Answer: 15 mm
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Consider a steel guitar string of initial length l=1.00m and cross-sectional area a=0.500mm2. the young's modulus of the steel is ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers