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4 August, 06:44

A 12 n cart is moving on a horizontal surface with a coefficient of kinetic friction of 0.20. what force of friction must be overcome to keep the object moving at a constant velocity?

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  1. 4 August, 09:42
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    We must remember that the total net force equation at constant velocity is:

    F - Ff = 0

    of

    F - µN = 0

    Using Newton's 2nd Law of Motion:

    F = m a

    Where,

    F = net force acting on the body

    m = mass of the body

    a = acceleration of the body

    Since the cart is moving at a constant velocity, then acceleration is zero, hence the working equation simplifies to

    F = net Force = 0

    Therefore,

    F - µN = 0

    where

    µ = coefficient of friction = 0.20

    N = normal force acting on the cart = 12 N

    Therefore,

    F - 0.20 (12) = 0

    F = 2.4 N
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