How does the change in the sa/v ratio compare with the change in distance from the center of the cell to the nearest face?

Question

Physics

Kirsten Sexton

8 October, 13:38

How does the change in the sa/v ratio compare with the change in distance from the center of the cell to the nearest face?

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Answers (1)

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Kaila Orr · Answer 1

Answer: I'm pretty sure the SA / V ratio would get smaller. Assume that the cell is more or less spherical. SA = 4 (pi) r^2, while V = (3/4) (pi) r^3. The ratio = (4 (pi) r^2) / ((3/4) (pi) r^3), which can be simplified to 3/r. Thus, the larger r gets, the smaller the ratio becomes.