What is the power output of an electric motor

that lifts a 2.0-kilogram block 15 meters

vertically in 6.0 seconds?

(1) 5.0 J (3) 49 J

(2) 5.0 W (4) 49 W

Mass of the block = 2.0 kg

Value of gravity = 9.81 m/s^2

Distance upto which the mass is lifted = 15 meters

Time taken to lift the mass of the block = 6.0 seconds

Now we already know

Work Done = Mass * Gravity * Distance

= 2 * 9.81 * 15

= 294 Joules

Then

Power Output = Work Done/Time

= 294/6

= 49 Watts

So the power output of the electric motor is 49 watts. The correct option among all the options given in the question is option "4".