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25 June, 02:30

A sand core used to form the internal surfaces of a steel casting experiences a buoyancy force of 225 n. the volume of the mold cavity forming the outside surfaces of the casting = 4840 cm3. what is the weight (in kg) of the final casting? ignore considerations of shrinkage

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  1. 25 June, 06:11
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    Newton’s second law gives us the relationship of force F, mass m and acceleration a. The formula is given as:

    F = m a - - > 1

    However we also know that the relationship of mass m, density ρ, and volume V is:

    m = V ρ - - > 2

    Therefore substituting equation 2 to equation 1:

    F = ρ V a = ρ V g

    where a is acceleration due to gravity, ρ is density of water and V is the volume of the casting, therefore:

    F = (1x10^-3 kg/cm^3) (4840 cm^3) (9.8 m/s^2)

    F = 47.432 kg m/s^2

    F = 47.432 N

    Going back to equation 1:

    47.432 N = m (9.8 m/s^2)

    m = 4.84 kg

    Hence the weight of the final casting is 4.84 kg
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