A 25.0-meter length of platinum wire with a cross-sectional area of 3.50 * 10^-6 meter^2 has a resistance

of 0.757 ohm at 20°C. Calculate the resistivity of the wire. [Show all work, including the equation and

substitution with units.]

Question

Physics

Akira Copeland

6 October, 18:42

A 25.0-meter length of platinum wire with a cross-sectional area of 3.50 * 10^-6 meter^2 has a resistance

of 0.757 ohm at 20°C. Calculate the resistivity of the wire. [Show all work, including the equation and

substitution with units.]

+3

Answers (1)

Know the Answer?

Jakob Stevens · Answer 1

R = (rou * L) / area

where R is the wire resistance

rou: resistivity of the wire material

L : wire length

A : cross section area of wire

by sub.

0.757 = (rou*25) / 3.5*10^-6

25*rou = 2.6495*10^-6

rou = 1.0598*10^-7 ohm. m

A 25.0-meter length of platinum wire with a cross-sectional area of 3.50 * 10^-6 meter^2 has a resistanceof 0.757 ohm at 20°C. Calculate the resistivity of the wire. [Show all work, including the equation andsubstitution with units.]

A 25.0-meter length of platinum wire with a cross-sectional area of 3.50 * 10^-6 meter^2 has a resistance

of 0.757 ohm at 20°C. Calculate the resistivity of the wire. [Show all work, including the equation and

substitution with units.]