Consider the example of a positive charge q moving in the negative z-direction with speed v with the local magnetic field of magnitude B in the z-direction.

Find F, the magnitude of the magnetic force acting on the particle. Express your answer in terms of v, q, B, and other quantities given in the problem statement.

Question

Physics

Catherine Vega

6 September, 08:31

Consider the example of a positive charge q moving in the negative z-direction with speed v with the local magnetic field of magnitude B in the z-direction.

Find F, the magnitude of the magnetic force acting on the particle. Express your answer in terms of v, q, B, and other quantities given in the problem statement.

+2

Answers (1)

Know the Answer?

Khloe Mcclain · Answer 1

F = 0

Explanation:

This problem can be solved by using the equation for the force produced by a magnetic field over a charge

F = qv X B

That is, the cross product between velocity and the magnetic field.

In this case, v is in the negative z-direction v = - v k^,

and the magnetic field is in the positive z-direction B = z k^

Hence, the cross product is

F = qv X B = 0i^ - 0j^ + 0k^ = 0

In this case the net force is zero due to both velocity and magnetic field vectors are in the z-direction