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6 September, 08:31

Consider the example of a positive charge q moving in the negative z-direction with speed v with the local magnetic field of magnitude B in the z-direction.

Find F, the magnitude of the magnetic force acting on the particle. Express your answer in terms of v, q, B, and other quantities given in the problem statement.

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  1. 6 September, 08:50
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    F = 0

    Explanation:

    This problem can be solved by using the equation for the force produced by a magnetic field over a charge

    F = qv X B

    That is, the cross product between velocity and the magnetic field.

    In this case, v is in the negative z-direction v = - v k^,

    and the magnetic field is in the positive z-direction B = z k^

    Hence, the cross product is

    F = qv X B = 0i^ - 0j^ + 0k^ = 0

    In this case the net force is zero due to both velocity and magnetic field vectors are in the z-direction
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