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27 July, 10:49

A rifle with a mass of m1 = 3.4 kg fires a bullet with a mass of 7.7 g (0.0077 kg). The bullet moves with a velocity of 860 m/s after the rifle is fired. If external forces acting on the rifle can be ignored, what is the magnitude of the recoil velocity of the rifle?

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  1. 27 July, 11:17
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    The magnitude of the recoil is v = 1.95 m/s

    Explanation:

    The momentum of bullet

    P = m*v

    P = 0.0077kg x 860m/s

    P = 6.622 kg m/s

    Now using the law of conservation of momentum we have,

    P1 + P2 = 0

    Now solve to V2 to find the velocity of the rifle so:

    m1*v1 + m2*v2 = 0

    3.4kg*v1 + 6.622 kg m/s = 0

    3.4 kg*v1 = - 6.622 kg m/s

    v1 = 6.622/3.4

    v1 = 1.95 m/s
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